Question

Derivation Of the second equation of motion
S=ut + 1/2at^2

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​Thanks​

Answer 1

Explanation:

so here in the graph, we have a velocity-time

so, in the diagram, we see that there is a triangle(DCB) and a rectangle(OACB). we know that the area under the velocity-time graph gives us the distance the body has travelled.

so,

distance=s=area of the triangle(BCD) + area of the rectangle(OABC)

now refer the attachments

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