Question

derivation Of third equation of motion
${v}^{2} - {u}^{2} = 2as$
​

Answer 1

Explanation:

so we have a velocity-time graph over here

so now refer the attachments

hope this helps you and please mark it as the brainliest

Cheers :)

Answer 2

$\boxed{\huge\tt\color{aqua}answer}$

Third equation of motion is,

$v^2 = u^2 +2as$

$We \: know \: that</strong></p><p></p><p><strong>\</strong><strong>\</strong><strong> </strong><strong>V = u + at</strong><strong> </strong></p><p></p><p></p><p><strong>[tex]V = u + at$

$<strong> </strong><strong>\implies \: v-u = at </strong></p><p><strong>[</strong><strong>tex</strong><strong>]</strong><strong>\implies \: v-u = at$

or,

$\implies t = \frac{v - u}{a}$

$Also \: we \: know \: that \: \\ </strong></p><p><strong>[tex]Also \: we \: know \: that \: \\ Distance = average \: velocity \: X \: Time$

$\therefore \: s = (\frac{v + u}{2})( \frac{v - u}{a} )$

$\implies \: s = \frac{ {v}^{2} - {u}^{2} }{2a}$

$\implies \:2a s = { {v}^{2} - {u}^{2} }$

$\implies \: {v}^{2} = {u}^{2} - 2as$