derivation of trigonometric ratios of 0 and 90
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first consider a triangle ABC and let B=90
now assume A=x...then C becomes (90-x)[since angle sum property]
now find all trigonometric ratios of x...and also for 90-x
tyen u can observe that
sin x=(cos 90-x)
cos x=sin (90-x)
tan x =cot (90-x)
cosec x=sec(90-x)
sec x=cosec(90-x)
cot x=tan(90-x)
now assume A=x...then C becomes (90-x)[since angle sum property]
now find all trigonometric ratios of x...and also for 90-x
tyen u can observe that
sin x=(cos 90-x)
cos x=sin (90-x)
tan x =cot (90-x)
cosec x=sec(90-x)
sec x=cosec(90-x)
cot x=tan(90-x)
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