Question

Derivation of v2 - u2= 2as

Answer 1

Derivation of 3rd law of motion -

v^2 - u^2 = 2as.

( final velocity^2 - initial velocity^2) = 2 × acceleration × distance.

We can depict the equation from a velocity time graph as follows:

HOPE IT HELPS! Mark as brainlist if it satisfies you dear

Answer 2

from the second equation of motion we have:

s=ut+1/2at^2
and from the first equation of motion we have:
v=u+at
this can be rearranged and written as:
at=v-u
or t=v-u/t
putting this value of t in equation (1) we get:
s=u(v-u)/a +1/2a(v-u/a)^2
s=uv-u^2/a + v^2+u^2-2uv/2a
s=2uv-2u^2+v^2+u^2-2uv/2a
2as=v^2-u^2
v^2-u^2=2as