Question

Derivation of wheat stone bridge principle
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Answer 1

Answer:

The current enters the galvanometer and divides into two equal magnitude currents as I1 and I2. The following condition exists when the current through a galvanometer is zero,

I1P=I2R (1)

The currents in the bridge, in a balanced condition, is expressed as follows:

I1=I3=EP+Q I2=I4=ER+S

Here, E is the emf of the battery.

By substituting the value of I1 and I2 in equation (1), we get

PEP+Q=RER+S

PP+Q=RR+S

P(R+S)=R(P+Q)

PR+PS=RP+RQ

PS=RQ

(2)

R=PQ×S

Explanation:

hope it will help you....☺️

Answer 2

Explanation:

ᴛʜᴇ ᴡʜᴇᴀᴛꜱᴛᴏɴᴇ ʙʀɪᴅɢᴇ ᴡᴏʀᴋꜱ ᴏɴ ᴛʜᴇ ᴘʀɪɴᴄɪᴘʟᴇ ᴏꜰ ɴᴜʟʟ ᴅᴇꜰʟᴇᴄᴛɪᴏɴ, ɪ.ᴇ. ᴛʜᴇ ʀᴀᴛɪᴏ ᴏꜰ ᴛʜᴇɪʀ ʀᴇꜱɪꜱᴛᴀɴᴄᴇꜱ ᴀʀᴇ ᴇQᴜᴀʟ ᴀɴᴅ ɴᴏ ᴄᴜʀʀᴇɴᴛ ꜰʟᴏᴡꜱ ᴛʜʀᴏᴜɢʜ ᴛʜᴇ ᴄɪʀᴄᴜɪᴛ. ᴜɴᴅᴇʀ ɴᴏʀᴍᴀʟ ᴄᴏɴᴅɪᴛɪᴏɴꜱ, ᴛʜᴇ ʙʀɪᴅɢᴇ ɪꜱ ɪɴ ᴛʜᴇ ᴜɴʙᴀʟᴀɴᴄᴇᴅ ᴄᴏɴᴅɪᴛɪᴏɴ ᴡʜᴇʀᴇ ᴄᴜʀʀᴇɴᴛ ꜰʟᴏᴡꜱ ᴛʜʀᴏᴜɢʜ ᴛʜᴇ ɢᴀʟᴠᴀɴᴏᴍᴇᴛᴇʀ.

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ.