derivation of young's double slit
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Young's double slit experiment:-
Let A and B be two fine slits, a small distance 'd' apart. Let them be illuminated by a monochromatic light of wavelength l.
MN in the screen is at a distance D from the slits AB. The waves from A and B superimpose upon each other and an interference pattern is obtained on the screen. The point C is equidistant from A and B and therefore the path difference between the waves will be zero and so the point C is of maximum intensity. It is called the central maximum.
For another point P at a distance 'x' from C, the path difference at P = BP - AP.
Now AB = EF = d, AE = BF = D
You are requested to post each query individually.
Young's double slit experiment:-
Let A and B be two fine slits, a small distance 'd' apart. Let them be illuminated by a monochromatic light of wavelength l.
MN in the screen is at a distance D from the slits AB. The waves from A and B superimpose upon each other and an interference pattern is obtained on the screen. The point C is equidistant from A and B and therefore the path difference between the waves will be zero and so the point C is of maximum intensity. It is called the central maximum.
For another point P at a distance 'x' from C, the path difference at P = BP - AP.
Now AB = EF = d, AE = BF = D
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