Question

derivative of 1/1+sinx​

Answer 1

Answer:

hey mate your answer is..

Step-by-step explanation:

$\frac{1}{1} + \sin(x) \\ = 1 + sin(x). \\ hope \: its \: helps...$

Answer 2

Let, y = 1/1+sinx

On differentiate with respect to x both the side :

$\frac{dy}{dx} = \frac{d}{dx} (\frac{1}{1 + sinx} ) \\ \\ = > \frac{d}{dx} {(1 + sinx)}^{ - 1} \\ \\ = > - \frac{1}{ ({1 + sinx)}^{2} } \times cosx \\ \\ = > - \frac{cosx}{ {(1 + sinx)}^{2} }$

I hope it will be helpful for you ✌️✌️

Mark it as brainliest and.....

Fóllòw MË ☺️☺️