Derivative of 1/rootx?
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Let f(x)=1√x, then y=1uandu=x12, since √x=x12.
Simplifying further, we have that y=uandu=x−12
The chain rule states dydx=dydu×dudx
This means we have to differentiate both functions and multiply them. Let's start with y.
By the power rule y'=1×u0=1.
Now for u:
Once again by the power rule we get:
u'=−12×x−12−1
u'=−12x−32
u'=−12√x3
f'(x)=y'×u'
f'(x)=1×−12√x3
f'(x)=−12√x3
Hopefully this helps!
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