Question

derivative of 1÷√(x+1)
$\frac{d}{dx} ( \frac{1}{ \sqrt{x + 1} } )$
find derivative?
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Answer 1

Answer:

$\frac{d}{dx}$$(\frac{1}{\sqrt{x-1} } )$

= $-\frac{1}{2(x-1)^\frac{3}{2} }$  [ apply chain rule to term $\frac{1}{\sqrt{x-1} }$ ]