derivative of 1/x+y
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HELLO ADITI,
HERE'S YOUR ANSWER.
=> Since 1y is constant with respect to x , the derivative of 1xy 1 x y with respect to x is 1yddx[1x] 1 y d d x [ 1 x ] . Rewrite 1x as x−1 . Differentiate using the Power Rule which states that ddx[xn] d d x [ x n ] is nxn−1 n x n - 1 where n=−1 .
HOPE IT HELPS YOU.
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Step-by-step explanation:
1/x +y
differenciatting with respect to
dy/dx - 1/x^2
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