derivative of 2(x-1)
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Answer:
Derivative rule:
ddxa−b=ddxa−ddxb
Here, we can substitute:
ddx(2x−1)
=[ddx2x]−[ddx−1]
(2x)'=2
(−1)'=0 (the derivative of any constant =0)
So:
[2]−[0]
=2−0
=2
Thus, solved.
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