derivative of 2x^2+1
Answers
Answered by
2
Step-by-step explanation:
4x
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Answered by
2
Answer:
By definition,
f
'
(
x
)
=
lim
h
→
0
f
(
x
+
h
)
−
f
(
x
)
h
so for
f
(
x
)
=
2
x
2
+
1
we have:
f
'
(
x
)
=
lim
h
→
0
{
(
2
(
x
+
h
)
2
+
1
)
−
(
2
x
2
+
1
)
}
h
f
'
(
x
)
=
lim
h
→
0
(
2
(
x
2
+
2
h
x
+
h
2
)
+
1
)
−
2
x
2
+
1
h
f
'
(
x
)
=
lim
h
→
0
2
x
2
+
4
h
x
+
2
h
2
+
1
−
2
x
2
−
1
h
f
'
(
x
)
=
lim
h
→
0
4
h
x
+
2
h
2
h
f
'
(
x
)
=
lim
h
→
0
(
4
x
+
2
h
)
f
'
(
x
)
=
4
x
Step-by-step explanation:
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