Question

Derivative of 2x + 3y = sinx

Answer 1

$<b>$
Hey there!

Solution:


2x + 3y = sinx


Now, Differentiate Both Sides wrt x.


We get:


Derivative of sinx = cosx


2 + 3 (dy/dx) = cosx


3 (dy/dx) = cosx - 2


dy/dx = (cosx - 2/3)




#Be Brainly.

Answer 2

given
2x+3y=sinx
d(2x+3y)/dx=d(sin x)/dx
d(2x)/dx+d(3y)/dx=d(,sin x)/dx
2(dx)/dx+3(dx)/dx=d(sin x)/dx
2+3d(y)/dx= cos x
3d(y)/dx=cos x-2
d(y)/dx= 1/3(cos-2)