Question

derivative of 3x^2+x-100

Answer 1

HOPE this helps you........

Answer 2

Answer:

$6x+1$

Step-by-step explanation:

$\implies \dfrac{d}{dx} \bigg[3x^{2}+x-100\bigg]$

Differentiation is linear. We can differentiate summands separately and pull out constant factors: [ a ⋅ u ( x ) + b ⋅ v ( x ) ] ′ = a ⋅ u ′ ( x ) + b ⋅ v ′ ( x )

$\implies 3\ . \ \dfrac{d}{dx}[x^{2}] + \dfrac{d}{dx}[x}] + \dfrac{d}{dx}[-100]$

$\implies 3\ .\ 2x+1+0$

$\implies 6x+1$