Question

derivative of √4-x??​

Answer 1

Answer:

$Ans) \frac{-1}{2\sqrt{4-x} }$

Step-by-step explanation:

$\frac{d}{dx} (\sqrt{x} ) = \frac{1}{2\sqrt{x} } \\\\\frac{d}{dx} (\sqrt{4-x}) = \frac{1}{2\sqrt{4-x} } * 0-1\\\\\frac{d}{dx} (\sqrt{4-x} ) = \frac{-1}{2\sqrt{4-x} }$