Question

derivative of √4-x??​

Answer 1

Answer:

Step-by-step explanation:

$let \: y \: = \sqrt{4 - x} \\ \frac{d}{dx}( \sqrt{4 - x)} \\ \frac{d}{dx} ( \sqrt{x)} = \frac{1}{2 \sqrt{x} } \\ \sqrt{4 - x} \\ \frac{d}{dx}( \sqrt{4 - x)} = \frac{1}{2 \sqrt{4 - x} } \times - 1 \\ \sqrt{4 - x} \\ \frac{d}{dx}( \sqrt{4 - x)} = \frac{ - 1}{2 \sqrt{4 - x} }$

Answer 2

Step-by-step explanation:

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