Question

derivative of a raise to power x​

Answer 1

Answer:

$a^{x}$ · lnx

Step-by-step explanation:

Let y = $a^{x}$

⇒ x = log(y) base a

Differentiate both sides w.r.t x gives :

⇒ 1 = $\frac{1}{y\ ln(a)}$ × $\frac{dy}{dx}$

⇒ $\frac{dy}{dx}$ = y· ln(a)

⇒ $\frac{d}{dx} a^{x} = a^{x} \ ln(a)$

Hoping that I have not made any mistakes, You're welcome.

Hope you have found my answer useful. If my answer deserves a brainliest, do mark it.

GeniusH