Derivative of cos inverse x with respect to sin inverse x
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Answered by
2
Answer:
-1
Step-by-step explanation:
d(cos^-1x)/dx = -1/√(1-x²)
d(sin^-1x)/dx = 1/√(1-x²)
now,
d(cos^-1x)/dx ÷ d(sin^-1x)/dx = -1
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