Question

derivative of d/dx cos(ax^2+b)​

Answer 1

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Actually Welcome to the Concept of the Derivatives of the Trigonometric functions.

Now here, we basically have to use the Chain Rule.

Chain Rule is such that, There is function inside a another function.

y= f(g(x))

so we differentitate it as,

=>dy/dx = d(f) /dx * d(g(x))/dx

so we get as,

=> dy/dx = f'(g(x)) * g'(x)

so here get as,

$y = \cos( {ax}^{2} + b )$

so after differentiation, we get as

⭐dy/dx = - sin ( ax^2+b) . 2ax

Answer 2

Answer:

Step-by-step explanation: