Question

Derivative of
d/dx x log x base e

Answer 1

Answer:

ln particular, the natural logarithm is the logarithmic function with base e. ln(e) = loge(x ). The graphs of two other logarithmic functions are ...

Step-by-step explanation:

please mark as brainleast answer

Answer 2

$\implies\dfrac{d(x \: logx)}{dx}$

Now differentiate the above expression using product rule :-

$\implies \: x \: \dfrac{d( logx)}{dx} + logx \: \dfrac{dx}{dx}$

$\implies \:( x \: \times \dfrac{1}{x} )+( logx \times 1)$

$\implies \:1+logx$

Answer :

$1+logx$

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Learn more :-

d(x^n)/dx = n x^(n-1)

d(log x)/dx = 1/x

d(e^x)/dx = e^x

d(sinx)/dx = cosx

d(cos x)/dx = -sin x

d(cosec x)/dx = -cot x cosec x

d(tan x)/dx = sec²x

d(sec x)/dx = secx tanx

d(cot x)/dx = - cosec² x