derivative of e^cot x^2
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Answered by
0
Answer:
Use the chain rule. The first issue here is the second power. According to the chain rule,
d
d
x
[
u
2
]
=
2
u
⋅
u
'
, and here we have
u
=
cot
(
x
)
, giving us
f
'
(
x
)
=
2
cot
(
x
)
⋅
d
d
x
[
cot
(
x
)
]
The derivative of
cot
(
x
)
is
−
csc
2
(
x
)
.
f
'
(
x
)
=
−
2
cot
(
x
)
csc
2
(
x
)
Answered by
0
Answer:
see the attached document for the steps
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