Question

derivative of e^log5x ?​

Answer 1

e^(log5x) = y

• Differentiating w.r.t.x

dy/dx = d/dx [ e^(log5x)]

= e^(log5x) . d/dx [ log5x ]

= e^(log5x) . 1/log5x . d/dx (5x)

= e^(log5x) . 1/log5x . 5

= 5e^(log5x) / log5x

•°• dy/dx = 5e^(log5x) / log5x

Derivative of e^log5x is 5e^(log5x) / log5x

Answer 2

e^(log5x) = y

Differentiating w.r.t.x

dy/dx = d/dx [ e^(log5x)]

= e^(log5x) . d/dx [ log5x ]

= e^(log5x) . 1/log5x . d/dx (5x)

= e^(log5x) . 1/log5x . 5

= 5e^(log5x) / log5x

•°• dy/dx = 5e^(log5x) / log5x

Derivative of e^log5x is 5e^(log5x) / log5x