Math, asked by ihashir806, 3 months ago

Derivative of function
worot x
y = (secx + tan x)(secx-tan x)​

Answers

Answered by farhaanaarif84
1

Answer:

y

'

=

0

Explanation:

Start by rewriting in terms of sine and cosine. For this problem we use the identities

sec

θ

=

1

cos

θ

ad

tan

θ

=

sin

θ

cos

θ

.

y

=

(

1

cos

x

+

sin

x

cos

x

)

(

1

cos

x

sin

x

cos

x

)

y

=

(

1

+

sin

x

cos

x

)

(

1

sin

x

cos

x

)

y

=

1

sin

2

x

cos

2

x

y

=

cos

2

x

cos

2

x

y

=

1

The derivative of any constant is

0

.

y

'

=

0

Hopefully this helps!

Similar questions