Derivative of function
worot x
y = (secx + tan x)(secx-tan x)
Answers
Answered by
1
Answer:
y
'
=
0
Explanation:
Start by rewriting in terms of sine and cosine. For this problem we use the identities
sec
θ
=
1
cos
θ
ad
tan
θ
=
sin
θ
cos
θ
.
y
=
(
1
cos
x
+
sin
x
cos
x
)
(
1
cos
x
−
sin
x
cos
x
)
y
=
(
1
+
sin
x
cos
x
)
(
1
−
sin
x
cos
x
)
y
=
1
−
sin
2
x
cos
2
x
y
=
cos
2
x
cos
2
x
y
=
1
The derivative of any constant is
0
.
y
'
=
0
Hopefully this helps!
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