Question

derivative of log cosec²x/2​

Answer 1

Let y = log cosex^2x/2

=> dy/dx = 1/cosec^2x/2 . 2 cosecx/2 . (-cotx/2cosecx/2) .1/2

=> dy/dx = -sin^2x/2.cotx/2cosec^2x/2 = -cotx/2 × 1

=> dy/dx = -cotx/2

I hope it will help you ☺

Fóllòw Më ❤