Math, asked by yadavpratik6171, 9 months ago

Derivative of log(secx-tanx)

Answers

Answered by nadeemrramzan
0

Answer:

{secx(tanx-secx)}/(secx-tanx)

Answered by Bhoomika5617
1

Answer:

-secx

Step-by-step explanation:

d/dX(log(secx-tanx)= 1/secx-tanx){d/dx(secx-tanx)

=(secxtanx-sec^2x)/secx-tanx

= secx(tanx-secx)/secx-tanx

=-secx

Similar questions