Derivative of log sinx4 is:
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y =log sinx^4
y' =1/sin x^4 . cos x^4 . 4x^3
y'=4x^3.cot x^4
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♔Azhar♔
Answered by
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Step-by-step explanation:
y =log sinx^4
Since derivative of log x is 1/x and derivative of sin x^4 is cos x^4.
Therefore,
y' =1/sin x^4 . cos x^4 . 4x^3
y'=4x^3.cot x^4
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