derivative of logx^x
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We know that the base of ln(x) is e, so we plug e in for a in the derivative formula to get that the derivative formula of ln(x) is 1 / x(ln(e)). Now, recall that we said the logarithm loga (x) is equal to the number we raise a to get x. Therefore, ln(e) is equal to the number we raise e to in order to get e.
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logx^x=xlogx
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