Question

derivative of sech(lnx)​

Answer 1

Hello Mate ❤️

Answer:

We can easily obtain the derivative formula for the hyperbolic tangent:

(tanhx)′=(sinhxcoshx)′=(sinhx)

Thanks ☺️ ❤️

Answer 2

Answer -

____________________________________

• let y=cosh(lnx)
• ⇒y=12⋅(elnx −e−lnx).
• =12⋅(elnx+elnx−1).
• =12(x+x−1).
• dyd x=12(1+(−1)⋅x−2)=12(x2−1x2)
• =x2−12x2.

____________________________________

→ Hope it will help you ❣️❣️