Math, asked by saiteja230802, 11 months ago

derivative of sin(tan^_1(e^x)​

Answers

Answered by Kashmiripsyco
0

Answer:

let

y=sin{tan^-1(e^x)}

dy/dx=cos{tan^-1(e^x)}×1/√1+e^x×e^x

dy/dx=costan^-1(e^x) 1/√e^2x

hope it helps

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