derivative of sin² (2x+1)
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We have to use chain rule here,
sin^2 (2x+1) = 2sin(2x+1) * d(sin(2x+1))/dx
= 2sin(2x+1) cos(2x+1) * d(2x+1)/dx
= 2sin(2x+1)cos(2x+1) *2
= 4sin(2x+1)cos(2x+1)
= 2sin2(2x+1)
thus, derivative of sin^2 (2x+1)= 2sin2(2x+1)
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