Question

Derivative of sin2x, cos2x, Tan2x

Answer 1

d/dx sin2x=cos2x ×d/dx 2x

=cos 2x (2)
=2 cos 2x


d/dx cos2x = -sin2x (d/dx 2x)

=-sin2x (2)

= -2 sin2x

d/dx tan2x=sec^2 2x (d/dx 2x)

=sec^2 2x (2)

=2 sec^2 2x