derivative of sinx^3* cosx^3 wrt x
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see the Sol in the above page..hope this will help you..☺
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Ronny13:
oops sorry the derivative is very easy ... i was trying for the integration .... sorry n thankx as well
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using chain rule we can find its derivative
y = sin ³xcos³x
dy= d(sinxcosx)³
dy=3(sinxcosx)²d(sinxcosx)
dy=3(sinxcosx)²{sinx dcosx+ dsinx cosx }
dy= 3 (sinxcosx)²{cos²x-sin²x}
dy=3 (sinxcosx)²(cos2x)
y = sin ³xcos³x
dy= d(sinxcosx)³
dy=3(sinxcosx)²d(sinxcosx)
dy=3(sinxcosx)²{sinx dcosx+ dsinx cosx }
dy= 3 (sinxcosx)²{cos²x-sin²x}
dy=3 (sinxcosx)²(cos2x)
oops sorry the derivative is very easy ... i was trying for the integration .... sorry n thankx as well
oh k dude
good luck
can u do the integration .... i think substition needed apart from by parts
yeah sure ask in next question
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