derivative of tan sin x
Answers
Answered by
3
Answer:
Derivatives of Basic Trigonometric Functions
(sinx)′=cosx,(cosx)′=−sinx. Using the quotient rule it is easy to obtain an expression for the derivative of tangent: (tanx)′=(sinxcosx)′=(sinx)′cosx−sinx(cosx)′cos2x=cosx⋅cosx−sinx⋅(−sinx)cos2x
Answered by
0
Answer:
Cos x
Step-by-step explanation:
hope it helps you. happy to help
Attachments:
Similar questions