Question

Derivative of the above question

Answer 1

Answer:

Dividing numerator and denominator by 2

we get

$\frac{ {e}^{x} + {e}^{ - x} } {2} \div \frac{ {e}^{x} - {e}^{ - x} }{2}$

we get coshx / sinhx = cothx

derivative of cothx is - cosech^2x

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Answer 2

answer is in attachment