Question

derivative of y=√log e^x

Answer 1

$y = \sqrt{ log {e}^{x} } \\ \frac{dy}{dx} = \frac{1}{2 \sqrt{log {e}^{x} } } \frac{d}{dx} log {e}^{x} \\ \frac{dy}{dx} = \frac{1}{2 \sqrt{log {e}^{x} } } \frac{1}{ {e}^{x} } \frac{d}{dx} {e}^{x} \\ = \frac{1}{2 \sqrt{log {e}^{x} } } \frac{1}{ {e}^{x} } {e}^{x} \\ = \frac{1}{2 \sqrt{log {e}^{x} } }$