Math, asked by rajarshipatra5769, 28 days ago

Derivative of y =sec^-1x^2

Answers

Answered by sandy1816
1

y =  {sec}^{ - 1}  {x}^{2}  \\  \\  \frac{dy}{dx}  =  \frac{1}{ {x}^{2} \sqrt{ { ({x}^{2} })^{2} - 1 }   }  \frac{d}{dx}  {x}^{2}  \\  \\  \frac{dy}{dx}  =  \frac{2x}{ {x}^{2} \sqrt{ {x}^{4} - 1 }  }  \\  \\  \frac{dy}{dx}  =  \frac{2}{x \sqrt{ {x}^{4} - 1 } }

Similar questions