Question

derivative of y=x^3 tan(2x) +3x^5 sin(4x)

Answer 1

Answer:

dx

d

(sin

2

3x.tan

3

2x)=sin

2

3x×

dx

d

(tan

3

2x)+tan

3

2x×

dx

d

(sin

2

3x)

=sin

2

3x(3 tan

2

2xsec

2

2x.2)+tan

3

2x(2sin3x.cos3x.3)

=6sin

2

3xtan

2

2xsec

2

2x+6sin3xcos3xtan

3

2x

Step-by-step explanation:

Give me brainelist