Question

Derivatives of (2x+3)÷(3x+2)

Answer 1

Answer:

Step-by-step explanation:

let u= 2x + 3

let v= 3x + 2

then, $\frac{d}{dx} (\frac{u}{v}) = \frac{vu' - uv'}{v^{2} }$

hence, we'll get:

$\frac{d}{dx} (\frac{2x+3}{3x+2}) = \frac{(3x+2)(2)- (2x+3)(3)}{(3x+2)^{2} }$

=> $\frac{6x + 4 - 6x - 9}{(3x+2)^{2} } = \frac{-5}{(3x+2)^{2} }$

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