Question

derivativon for uniform circular motion....

Answer 1

Let the speed be ss.

We have, by definition,

s2=v⃗ ⋅v⃗ ;(1)(1)s2=v→⋅v→;thus

s2˙=v⃗ ˙⋅v⃗ +v⃗ ⋅v⃗ ˙=2v⃗ ˙⋅v⃗ =2a⃗ ⋅v⃗ =0,(2)(2)s2˙=v→˙⋅v→+v→⋅v→˙=2v→˙⋅v→=2a→⋅v→=0,

since a⃗ a→ is orthogonal to v⃗ v→. Thus s2s2 is constant, and so is ss.

Answer 2

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