⭐derivativon of first law of Kepler (law of orbit)
☺️✌️
Answers
Answered by
1
Case 1. e = 0.
Then
The orbit is a circle.
Now let
Then
Convert to Cartesian coordinates:
We now obtain Case 2: If e = 1, the orbit is a parabola.
Also if e > 1, then we get Case 3: If e > 1, the orbit is a hyperbola.
Now assume . Complete the square to get
Let , . Then distance from the center to the ellipse to the focus is c where .
So . So (0,0) is a focus of the ellipse. Note that the eccentricity of the ellipse is
.
Then
The orbit is a circle.
Now let
Then
Convert to Cartesian coordinates:
We now obtain Case 2: If e = 1, the orbit is a parabola.
Also if e > 1, then we get Case 3: If e > 1, the orbit is a hyperbola.
Now assume . Complete the square to get
Let , . Then distance from the center to the ellipse to the focus is c where .
So . So (0,0) is a focus of the ellipse. Note that the eccentricity of the ellipse is
.
Answered by
1
there is no derivation as such for the first law of Kepler..
the first law states that each planet revolves around the sun in an elliptical Orbit
A planet orbits the Sun in an ellipse, with the Sun at one focus of the ellipse
pls mark brainliest
the first law states that each planet revolves around the sun in an elliptical Orbit
A planet orbits the Sun in an ellipse, with the Sun at one focus of the ellipse
pls mark brainliest
Similar questions
Math,
7 months ago
Social Sciences,
7 months ago
Math,
7 months ago
World Languages,
1 year ago
Chemistry,
1 year ago
Math,
1 year ago