#Derive 1/R=1/R1+1/R2+1/R3. COMMON THE EASY ONE WHO WILL SOLVE IT? #PARALLEL CONNECTION#
Answers
Answer:
Consider three resistors having resistance R1, R2 and R3 are connected in parallel as shown in dig. Let r be the potential difference applied across the combination which is same for each resistor but current flowing through each resistor is different and total current is given by:
I = I1 + I2 + I3 (i)
by ohm's law : current is given by I = V/ Rp (ii)
(where Rp = equivalent resistance of parallel combination)
also, I1 = current flowing through resistance
R1 = V/ R1 (iii)
I2 = current flowing through resistance
R2 = V/ R2 (iv)
I3 = current flowing through resistance
R3 = V/ R3 (v)
putting the values from (ii), (iii), (iv) and (v) in equation (i)
V/Rp = V/ R1 + V/ R2 + V/ R3
V/Rp = V ( 1/R1 + 1/R2 + 1/R3)
OR
1/Rp = 1/R1 + 1/R2 + 1/R3