DERIVE : 1) v²-u^2 = 2as
2) v = u + at
3) s= ut + 1/2 at?^2
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Answer:
Explanation:
draw a velocity time graph for a body moving with uniform acceleration.
1. a = v - u/ t
v - u/ t = a
at = v - u
at + u = v
v = u + at
position - time relation
for that find the area of the graph
we will get
s = 1/2 x t x (v-u) + ut
substituting (v-u) as at
from, a = v - u / t
at = v - u
since s = 1/2 x t x at x ut
s = 1/2 at² + ut
position - velocity relation
find the area
1/2 x t (u + v )
substituting for t = v-u / a
from , a =v - u/ t
t = v - u / a
since
s = 1/2 (v - u /a) (u + v )
s= 1 / 2a ( v - u ) ( v + u)
s = 1 / 2a (v² - u²)
2as = v² - u²
hope it helps.....
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