Question

derive 2nd equation for motion

class 11

Answer 1

I have derived it plz comment on it

Answer 2

F∝(dp/dt)−>Eq.1F∝(dp/dt)−>Eq.1

since p=(m∗v)p=(m∗v)

=> dp=(m∗dv)−>Eq.2dp=(m∗dv)−>Eq.2

replacing dpdp in Eq.1 from Eq.2

F∝(m∗dv)/dt=m∗(dv/dt)F∝(m∗dv)/dt=m∗(dv/dt)

Acceleration : Rate of change of velocity per unit time = (dv/dt)(dv/dt)

F ∝m∗a∝m∗a

replacing proportionality using constant K

F=K∗m∗aF=K∗m∗a

Experiments tells us that the value of constant is 1; Thus

F=ma
hence proved