Question

derive 2nd equation of motion

Answer 1

 Second equation of motion:

s = ut + 1/2 at^2

sol.

Let the distance travelled by the body be “s”.

We know that

Distance = Average velocity X Time

Also, Average velocity = (u+v)/2

.: Distance (t) = (u+v)/2 X t …….eq.(1)

Again we know that:

v = u + at

substituting this value of “v” in eq.(2), we get

s = (u+u+at)/2 x t

=>s = (2u+at)/2 X t

=>s = (2ut+at^2)/2

=>s = 2ut/2 + at^2/2

or s = ut +1/2 at^2

Answer 2

Well, if you're referring to “Newton's 2nd Law Of Motion”, it's:

“F = MA”

It stands for that the “Pulling” or “Pushing”, on any object — the “FORCE” (F), is the direct result of the object's “Contained Stuff Capacity Amount” — the “MASS” (M), multiplied by its “Sudden Alteration In Both “Speed” & “Movement Course”” — the “Velocity”, which is what “ACCELERATION” (A) is.

So, in summary, “Force = Mass X Acceleration”.