Math, asked by rajdeeproykarmakar, 6 months ago

derive 3 equation of motion using graphical method​

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Answered by kanaktiwari2july
1

Answer:

Derivation of Third Equation of Motion by Graphical Method

Derivation of Third Equation of Motion by Graphical MethodS = ½ (Sum of Parallel Sides) × Height.

Derivation of Third Equation of Motion by Graphical MethodS = ½ (Sum of Parallel Sides) × Height.S=(OA+CB)×OC. Since, OA = u, CB = v, and OC = t. ...

Derivation of Third Equation of Motion by Graphical MethodS = ½ (Sum of Parallel Sides) × Height.S=(OA+CB)×OC. Since, OA = u, CB = v, and OC = t. ...S= ½ (u+v) × t. Now, since t = (v – u)/ a. ...

Derivation of Third Equation of Motion by Graphical MethodS = ½ (Sum of Parallel Sides) × Height.S=(OA+CB)×OC. Since, OA = u, CB = v, and OC = t. ...S= ½ (u+v) × t. Now, since t = (v – u)/ a. ...S= ½ ((u+v) × (v-u))/a. Rearranging the equation, we get.

Derivation of Third Equation of Motion by Graphical MethodS = ½ (Sum of Parallel Sides) × Height.S=(OA+CB)×OC. Since, OA = u, CB = v, and OC = t. ...S= ½ (u+v) × t. Now, since t = (v – u)/ a. ...S= ½ ((u+v) × (v-u))/a. Rearranging the equation, we get.S= ½ (v+u) × (v-u)/a.

Derivation of Third Equation of Motion by Graphical MethodS = ½ (Sum of Parallel Sides) × Height.S=(OA+CB)×OC. Since, OA = u, CB = v, and OC = t. ...S= ½ (u+v) × t. Now, since t = (v – u)/ a. ...S= ½ ((u+v) × (v-u))/a. Rearranging the equation, we get.S= ½ (v+u) × (v-u)/a.S = (v2-u2)/2a.

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