derive 3 rd eq of motion ising calclus method.
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How can I derive the 3rd equation of motion using calculus?
I think you are talking about Newton's 3rd equation of motion. It consists final velocity (v), initial velocity(u), displacement (s) and constant acceleration (a). The equation is as follows-
v²= u²+2as
Actually I don't know how to derive it. But here is some hints are provided.
You want it by integration.
(v² - u²) /2 indicates the integration of v dv limit u to v.
Here is the proof -
a= dv/dt……1
v=ds/dt……….2
from 1 & 2:
a ds/dt = v dv/ dt
implies a ds =v dv
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