Question

derive 3rd equation of motion graphically

Answer 1

so, distance travelled= s
= sumof parallel sides / 2× distance between parallel sides
s= OA+OB/2 × OC
But, OA= u, BC = v and OC = t
substituting the values , we get s = u+v×t/2
From equation 1 , v=u+at
, we get t = v-u/a
substituting the values of the
s=( v+u)(v-u)/2a
${v}^{2} - {u }^{2} = 2as$