Question

derive a expression for force exerted on test charge by a continuous charge distribution

Answer 1

Answer:

THE FORCE OF ATTRACTION OR REPULSION BETWEEN TWO POINT CHARGES IS DIRECTLY PROPORTIONAL TO PRODUCT OF TWO CHARGES AND INVERSELY PROPORTIONAL TO SQUARE OF DISTANCE BETWEEN THEM.

Explanation:

MATHEMATICALLY ,

F directly proportional to q1 q2 (1)

F inversely proportional to d^2 (2)

combining (1) & (2)

F proportional q1 q2

d^2

F = k q1 q2 [where k is constant of

d^2 proportionality]

and k is

K = 1/ 4 pi (absilen not) absilen r

putting value of k in

F = 1 q1 q2 / 4pi (absilen not) absilen r d^2