derive a formula for max. height reached by a body for a vertically projected body
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Explanation:
If a body is thrown vertically upwards with initial velocity u to a height h then there will be retardation (a=-g). So we have equations of motion as:
v=u-gt ………(1)
h=ut - 1/2gt^2 …….(2)
v^2-u^2=-2gh…….(3)
At maximum height v=0 so
From (3) we get
-u^2=-2gh
h=u^2/2g
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AnswEr :
Consider an object moving with an initial velocity 'u' reaches a maximum height 'h' in time 't' s.Upon reaching 'h' m ,the velocity of the object changes to 'v'
According to the Sign Convention,
Acceleration due to gravity would be '-g' m/s²
From the Third Kinematic Equation,
Maximum height reached by the object would be given by u²/2g
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