Physics, asked by 12341910, 11 months ago

derive a relation between kinetic energy and momentum 'p' of an object having mass m and velocity v

Answers

Answered by vinodgopinathan44
5


kinetic energy=(1÷2)mv×v
multiplying and dividing with m
kinetic energy=(m×m×v×v)÷2m
momentum=mv=p
p×p=m×m×v×v
kinetic energy =(p×p)÷2m
root of (2m×kinetic energy)=p

Answered by Anonymous
2

\huge\bold{Answer :}

We know that a Cricket Ball is much Heavier then a Tennis Ball. Suppose we throw a Cricket ball and a Tennis Ball, Both with the Same Velocity. It will be Found that More Force is required to stop the Cricket ball [ which has more mass ] and less force is required to stop the tennis ball [ which has less mass ].

<b>We can conclude that force required to stop a moving body is directly proportional to its mass

Now, if throw two cricket balls of same mass with different velocities, it will be found that more force would be required to stop that cricket ball which is moving with higher velocity and less force is required to the Stop the Cricket ball moving with lower velocity.

<b>So, We can conclude that the Force required to stop a moving body is also directly proportional to its velocity

Thus, The quantity of Motion ina body depends on the Mass and Velocity of the Body. This gives us the Term "Momentum" which is defined as the product of mass and Velocity of a body.

<b>THUS, MOMENTUM = MASS × VELOCITY

p = m × v.

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